MHTCET 11 Apr 2026 Shift 1 Paper

Concept:Acceleration due to gravity varies with height and depth from the earth's surface.Explanation:At a height $h$ above the surface, gravity is:$$g_h = g\left(\frac{R}{R+h}\right)^2$$As $h$ increases, $g_h$ decreases.At a depth $d$ below the surface, gravity is:$$g_d = g\left(1-\frac{d}{R}\right)$$As $d$ increases, $g_d$ also decreases.Therefore, Statement I is correct.For Statement II, if $h = d$, then compare:$$g_h = g\left(\frac{R}{R+h}\right)^2 \quad \text{and} \quad g_d = g\left(1-\frac{h}{R}\right)$$These two expressions are not generally equal.For small $h$, $g_h \approx g\left(1-\frac{2h}{R}\right)$, while $g_d = g\left(1-\frac{h}{R}\right)$.So the decrease in gravity is different for height and depth even when $h = d$.Hence, Statement II is incorrect.Answer:Option C — Statement I is correct but Statement II is incorrect.