MHTCET 11 Apr 2026 Shift 2 Paper

Concept:When charged capacitors are isolated and reconnected, their charges remain unchanged. The total energy depends only on total charge and capacitance, so it stays constant.Explanation:Let each capacitor have capacitance $C$.Initially in parallel, each capacitor has potential difference $V$, so charge on each is $q = CV$.Total initial energy is$$U_{\text{initial}} = n \times \frac{1}{2} C V^2 = \frac{1}{2} n C V^2.$$After separation, each capacitor retains its charge $CV$.When joined in series, the potential difference across each capacitor is still $V$.Therefore, the total potential difference becomes$$V_{\text{total}} = nV.$$The equivalent capacitance of the series combination is $\frac{C}{n}$.So final energy is$$U_{\text{final}} = \frac{1}{2} \cdot \frac{C}{n} \cdot (nV)^2 = \frac{1}{2} n C V^2.$$Hence, $U_{\text{final}} = U_{\text{initial}}$, so total energy does not change.Answer:The potential difference becomes $nV$ and the total energy remains the same.Thus, the correct option is C.