MHTCET 11 Apr 2026 Shift 2 Paper

Concept:Mutual induction causes an emf in the secondary coil when the primary current changes with time.Explanation:The instantaneous primary current is alternating, so we write it as$$I = I_0 \sin \omega t$$The induced emf in the secondary coil is given by$$e = -M \frac{dI}{dt}$$For a sinusoidal current, the peak value of this induced emf becomes$$e_0 = M \omega I_0$$Here, the peak current is$$I_0 = \frac{2}{\pi} \ \mathrm{A}$$The coefficient of mutual inductance is$$M = 1 \ \mathrm{H}$$And the frequency of the AC is$$f = 50 \ \mathrm{Hz}$$So the angular frequency is$$\omega = 2\pi f = 2\pi \times 50 = 100\pi \ \mathrm{rad/s}$$Substituting these values:$$e_0 = 1 \times 100\pi \times \frac{2}{\pi}$$$$e_0 = 200 \ \mathrm{V}$$Thus, the peak emf induced in the secondary coil is $200 \ \mathrm{V}$.Answer:$$200 \ \mathrm{V}$$Correct option: D.