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MHTCET 11 Apr 2026 Shift 2 Paper

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Question : 51 of 150

Marks: +1, -0

Calculate the volume of 99 g of

\mathrm{CO}_{2}

at STP ?

22.4 L
50.4 L
67.2 L
89.6 L

Solution:

Concept:

At STP, one mole of any gas occupies

22.4 \, \mathrm{L}

.

The volume of a gas is found by multiplying the number of moles by

22.4 \, \mathrm{L \, mol^{-1}}

.

Explanation:

The molar mass of

\mathrm{CO}_2

is:

12 + 2(16) = 44 \, \mathrm{g \, mol^{-1}}

So,

44 \, \mathrm{g}

of

\mathrm{CO}_2

equals

1

mole.

Number of moles in

99 \, \mathrm{g}

of

\mathrm{CO}_2

:

\text{Moles} = \frac{99}{44} = 2.25

At STP,

1

mole of gas occupies

22.4 \, \mathrm{L}

.

Therefore, volume of

2.25

moles:

2.25 \times 22.4 = 50.4 \, \mathrm{L}

Answer:

50.4 \, \mathrm{L}

Option B.

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