MHTCET 11 May 2024 Shift 2 Paper

Concept:When light passes through multiple transparent liquid layers, the total apparent depth is the sum of each layer's real depth divided by its refractive index.Explanation:For a single liquid layer, the apparent depth is given by $\frac{\text{real depth}}{\text{refractive index}}$.For two immiscible liquids stacked in a vessel, the total apparent depth is:$$\text{Apparent depth} = \frac{d_1}{n_1} + \frac{d_2}{n_2}$$Here, $d_1 = 40\ \text{cm}$ and $n_1 = 1.6$ for the first liquid.For the second liquid, $d_2 = 30\ \text{cm}$ and $n_2 = 1.5$.Substituting these values:$$\text{Apparent depth} = \frac{40}{1.6} + \frac{30}{1.5}$$Calculating each term:$$\frac{40}{1.6} = 25\ \text{cm}$$$$\frac{30}{1.5} = 20\ \text{cm}$$Adding these contributions gives:$$25 + 20 = 45\ \text{cm}$$Thus, the vessel appears to have a total depth of 45 cm when viewed normally.Answer:The apparent depth of the vessel is $45\ \text{cm}$, which matches option C.