Concept:Acid-catalysed hydration of an alkene follows Markovnikov's rule and gives an alcohol as the major product.
Explanation:The given reactant is 1-methylcyclohexene, which contains a double bond.
In the presence of dilute acid, water adds across this
C=C double bond.
First, the
Ï€ electrons attack
H+, and the proton adds to the less substituted carbon of the double bond.
This forms a more stable tertiary carbocation at the carbon atom that bears the methyl group.
Next, a water molecule attacks this carbocation, forming an oxonium ion.
Finally, loss of
H+ from the oxonium ion gives the alcohol.
Thus, the hydroxyl group attaches to the same carbon that already carries the methyl group.
The product A is therefore 1-methylcyclohexanol.
Answer:The structure of A is 1-methylcyclohexanol, which corresponds to option B.
