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MHTCET 13 May 2023 Shift 1 Solved Paper
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© examsnet.com
Question : 117
Total: 150
In resonance tube, first and second resonance are obtained at depths
22.7
cm
and
70.2
cm
respectively. The third resonance will be obtained at a depth
117.7
cm
92.9
cm
115.5
cm
113.5
cm
Validate
Solution:
First resonance will occur at
l
1
+
x
=
λ
4
...(i)
Second resonance will occur at
l
2
+
x
=
3
λ
4
...(ii)
l
2
+
x
=
3
(
l
1
+
x
)
l
2
+
x
=
3
l
1
+
3
x
2
x
=
l
2
−
3
l
1
∴
x
=
l
2
−
3
l
1
2
=
70.2
−
68.1
2
=
1.05
cm
∴
Third resonance occurs at
l
3
+
x
=
5
λ
4
∴
l
3
=
5
(
l
1
+
x
)
−
x
=
5
l
1
+
4
x
=
113.5
+
4.2
=
117.7
cm
© examsnet.com
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