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MHTCET 13 May 2023 Shift 1 Solved Paper
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© examsnet.com
Question : 35
Total: 150
Calculate the work done in the following reaction at
300
K
and at constant pressure.
(
R
=
8.314
J
K
−
1
mol
−
1
)
4
HCl
(
g
)
+
O
2
(
g
)
⟶
2
Cl
2
(
g
)
+
2
H
2
O
(
g
)
−
7482
J
−
4988
J
2494
J
3200
J
Validate
Solution:
W
=
−
∆
n
g
RT
=
−
(
4
−
5
)
×
8.314
×
300
=
1
×
8.314
×
300
=
2494.2
J
© examsnet.com
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