A uniformly charged semicircular arc of radius ' r ' has linear charge density ' \lambda '. The electric field at its centre is ( \epsilon_0= permittivity of free space)

\frac{\lambda}{4 \epsilon_0 {\r}}

\frac{2 \pi \epsilon_0}{\lambda}

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MHTCET 14 May 2023 Shift 1 Solved Paper

Section: Physics

Question : 128 of 150

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