MHTCET 15 May 2024 Shift 1 Paper

Concept:For cyclic alcohols, number the ring so that the carbon bearing $-\mathrm{OH}$ gets the lowest possible locant.Explanation:The given structure has a five-membered saturated ring, so the parent name is cyclopentane.The $-\mathrm{OH}$ group is the principal functional group, so the suffix becomes $-\mathrm{ol}$, giving cyclopentanol.Numbering starts from the carbon attached to $-\mathrm{OH}$, making it C1.The ring is numbered in the direction that gives the methyl substituents the lowest locants.The two methyl groups are located at C2 and C5.Therefore, the correct IUPAC name is 2,5-dimethylcyclopentanol.The open-chain names in options A and B are incorrect because a ring is present.Option D is not preferred because it assigns locant 2 to the $-\mathrm{OH}$ carbon, even though locant 1 is possible.Answer:C. 2,5-Dimethylcyclopentanol