Identify product ' B ' in following reaction. {CH}₃-{I}+{KCN} A [C₂ {H}₂ {OH}]{{Na}} B

Correct Answer is : CH3CH2NH2{CH}₃ {CH}₂ {NH}₂CH3CH2NH2

Correct Answer is : CH3CH2NH2{CH}₃ {CH}₂ {NH}₂CH3CH2NH2

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MHTCET 15 May 2024 Shift 2 Paper

Question : 93 of 150

Marks: +1, -0

\mathrm{CH}_{3}-\mathrm{I}+\mathrm{KCN} \longrightarrow A \xrightarrow[C_{2} \mathrm{H}_{2} \mathrm{OH}]{\mathrm{Na}} B

Solution:

Concept:

Alkyl halides react with

\mathrm{KCN}

to form nitriles, which on reduction give primary amines.

Explanation:

\mathrm{CH}_3\mathrm{I}

reacts with

\mathrm{KCN}

via nucleophilic substitution to form methyl cyanide (ethanenitrile),

A

So,

A

\mathrm{CH}_3\mathrm{CN}

Then

A

is reduced using sodium metal in ethanol (

\mathrm{C}_2\mathrm{H}_5\mathrm{OH}

This reduction converts the

-\mathrm{CN}

group into

-\mathrm{CH}_2\mathrm{NH}_2

Therefore,

B

is ethylamine,

\mathrm{CH}_3\mathrm{CH}_2\mathrm{NH}_2

Answer:

B = \mathrm{CH}_3\mathrm{CH}_2\mathrm{NH}_2

, which is option D.

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