Concept:Use the chain rule for a logarithm with any base: dxdlogau=ulogau′.Explanation:Let y=log8(log5x).Set u=log5x. Then y=log8u.Differentiate the outer logarithm:dxdy=ulog81⋅dxduNow differentiate u=log5x:dxdu=xlog51Substitute u=log5x and dxdu into the derivative:dxdy=log5xlog81⋅xlog51Since log5x=log5logx, the log5 factors cancel:dxdy=xlog8logx1Answer:The correct option is D: xlog8logx1.