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MHTCET 16 Apr 2026 Shift 1 Paper

Question : 63 of 150

Marks: +1, -0

\mathrm{KO}_{2}

Solution:

Concept:

\mathrm{KO}_2

is a superoxide. The average oxidation number of oxygen in superoxides is

-\frac{1}{2}

Explanation:

Let the oxidation number of each oxygen atom be

x

Potassium (

\mathrm{K}

) has an oxidation number of

+1

The compound is electrically neutral, so:

+1 + 2x = 0

2x = -1

x = -\frac{1}{2}

Thus, the average oxidation number of oxygen in

\mathrm{KO}_2

-\frac{1}{2}

Answer:

Option B:

-\frac{1}{2}

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