Concept:Use the negation of an implication: ¬(A→B)≡A∧¬B.Explanation:Given statement: (p∧q)→((p∨r)→∼q).Negate it using ¬(A→B)≡A∧¬B.So, negation = (p∧q)∧¬((p∨r)→∼q).Again apply the same rule inside: ¬((p∨r)→∼q)≡(p∨r)∧∼(∼q).Since ∼(∼q)≡q, we get (p∨r)∧q.Therefore, the full negation becomes (p∧q)∧(p∨r)∧q.Because (p∧q) is true, it forces p to be true, making (p∨r) already true.Also q is already included in p∧q.Thus the expression simplifies to p∧q.Answer:Option A: p∧q.