MHTCET 17 Apr 2026 Shift 2 Paper

Concept:Inductive reactance is $X_L = \omega L$ and capacitive reactance is $X_C = \frac{1}{\omega C}$.When the angular frequency changes, these two reactances change in opposite ways.Explanation:Initially, the capacitive reactance and inductive reactance are equal, so $X_L = X_C$.Let the initial angular frequency be $\omega$.When the angular frequency is doubled, the new angular frequency becomes $2\omega$.New inductive reactance: $X_L' = (2\omega)L = 2X_L$.New capacitive reactance: $X_C' = \frac{1}{(2\omega)C} = \frac{X_C}{2}$.The required ratio of the new capacitive reactance to the new inductive reactance is:$$\frac{X_C'}{X_L'} = \frac{\frac{X_C}{2}}{2X_L}$$Since initially $X_C = X_L$, substitute to get:$$\frac{X_C'}{X_L'} = \frac{1}{4}$$Answer:The ratio is $\frac{1}{4}$, so the correct option is A. $\frac{1}{4}$.