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MHTCET 19 Apr 2026 Shift 1 Paper

Question : 62 of 150

Marks: +1, -0

5 \times 10^{-4} \mathrm{M} \mathrm{H}^{+}

ion?

Solution:

Concept:

The pH of a solution is calculated from the negative logarithm of the hydrogen ion concentration.

Explanation:

The formula for pH is:

\mathrm{pH} = -\log[\mathrm{H}^{+}]

Given that

[\mathrm{H}^{+}] = 5 \times 10^{-4}\ \mathrm{M}

Substitute this value into the formula:

\mathrm{pH} = -\log(5 \times 10^{-4})

Use the property of logarithms:

\log(a \times b) = \log a + \log b

So,

\log(5 \times 10^{-4}) = \log 5 + \log 10^{-4}

We know

\log 5 = 0.699

and

\log 10^{-4} = -4

Thus,

\log(5 \times 10^{-4}) = 0.699 - 4 = -3.301

Therefore,

\mathrm{pH} = -(-3.301) = 3.301

Answer:

The pH of the solution is

3.301

Correct option: B.

3.301

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