MHTCET 19 Apr 2026 Shift 1 Paper

Concept:The Wurtz reaction couples two alkyl halides with sodium metal in dry ether to form higher alkanes.Explanation:When methyl bromide and ethyl bromide are mixed, three possible coupling products can form.Two methyl bromide molecules combine to give ethane.$$2\mathrm{CH_3Br} + 2\mathrm{Na} \rightarrow \mathrm{CH_3CH_3} + 2\mathrm{NaBr}$$Methyl bromide and ethyl bromide combine to give propane.$$\mathrm{CH_3Br} + \mathrm{C_2H_5Br} + 2\mathrm{Na} \rightarrow \mathrm{CH_3CH_2CH_3} + 2\mathrm{NaBr}$$Two ethyl bromide molecules combine to give n-butane.$$2\mathrm{C_2H_5Br} + 2\mathrm{Na} \rightarrow \mathrm{C_4H_{10}} + 2\mathrm{NaBr}$$Here $\mathrm{C_4H_{10}}$ is the straight-chain alkane, n-butane.No branched alkane is produced in this reaction.Therefore, 2-methylpropane is not obtained.Answer:The compound not obtained is 2-methylpropane (Option D).