MHTCET 20 Apr 2026 Shift 2 Paper

Concept:Acceleration due to gravity ($g$) is maximum at Earth's surface and decreases both when moving upward and when moving downward.Explanation:At a height $h$, the value is $g_h = \frac{g}{\left(1+\frac{h}{R}\right)^2}$.As $h$ increases, $g_h$ decreases.At a depth $d$, the value is $g_d = g\left(1-\frac{d}{R}\right)$.As $d$ increases, $g_d$ decreases.Therefore, Option A is correct.Option B is incorrect because for $h = d$, $g_h \approx g\left(1-\frac{2h}{R}\right)$, while $g_d = g\left(1-\frac{d}{R}\right)$; these are not equal.Option C is incorrect because with $h = 640$ km and $R = 6400$ km, $\frac{h}{R} = 0.1$, so $g_h \approx g(1 - 0.2) = 0.8g$, giving a decrease of $20\%$, not $10\%$.Option D is incorrect because at the poles, there is no centripetal effect due to Earth's rotation, so gravity is not reduced by rotation.Answer:The correct statement is Option A.