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MHTCET 2016 Math Solved Paper
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© examsnet.com
Question : 12
Total: 50
In ΔABC,
(
a
−
b
)
2
c
o
s
2
C
2
+
(
a
+
b
)
2
s
i
n
2
C
2
is equal to
b
2
c
2
a
2
a
2
+
b
2
+
c
2
Validate
Solution:
(b)
(
a
−
b
)
2
cos
2
C
2
+
(
a
+
b
)
2
sin
2
C
2
=
(
a
2
+
b
2
−
2
a
b
)
cos
2
C
2
+
(
a
2
+
b
2
+
2
a
b
)
sin
2
C
2
=
a
2
(
cos
2
C
2
+
sin
2
C
2
)
+
b
2
(
cos
2
C
2
+
sin
2
C
2
)
-
2
a
b
(
cos
2
C
2
−
sin
2
C
2
)
=
a
2
+
b
2
−
2
a
b
cos
C
[
∵
(
cos
2
C
2
+
sin
2
C
2
)
=
cos
C
]
=
a
2
+
b
2
-
2
a
b
(
a
2
+
b
2
−
c
2
2
a
b
)
=
c
2
[
∵
cos
C
=
a
2
+
b
2
−
c
2
2
a
b
]
© examsnet.com
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