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MHTCET 2016 Physics Solved Paper
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© examsnet.com
Question : 19
Total: 50
A particle moves along a circle of radius r with constant tangential acceleration. If the velocity of the particle is v at the end of second revolution, after the revolution has started, then the tangential acceleration is
v
2
8
π
r
v
2
6
π
r
v
2
2
π
r
v
2
2
π
r
Validate
Solution:
(a) Using third equation of motion,
v
2
=
u
2
+ 2as
We have given
Initial velocity, u = 0
S = 2 x 2πr = 4πr
So,
v
2
= 2a x 4πr ⇒ a =
v
2
8
π
r
(using (i))
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