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MHTCET 2016 Physics Solved Paper
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© examsnet.com
Question : 4
Total: 50
An electron of mass m has de-Broglie wavelength λ when accelerated through potential difference V. When proton of mass M, is accelerated through potential difference 9 V, the de-Broglie wavelength associated with it will be (Assume that wavelength is determined at low voltage)
λ
3
√
M
m
λ
3
M
m
λ
3
√
m
M
λ
3
m
M
Validate
Solution:
(c) From de-Broglie relation,
λ
=
h
p
⇒
λ
=
h
√
2
m
K
E
=
h
√
2
m
q
V
⇒ λ ∝
1
√
q
V
m
For electron
λ
e
∝
1
√
e
V
m
.....(i)
For proton,
λ
p
∝
1
√
e
9
V
m
.....(ii)
where, e is the charge on proton, potential difference = 9 V and Mass of proton = m From eqs. (i) and (ii)
λ
e
λ
p
=
√
e
9
V
m
e
V
m
⇒
λ
p
=
λ
e
3
√
m
M
© examsnet.com
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