MHTCET 23 Apr 2025 Shift 2 Paper

Concept:Brewster's law states that $\tan \theta_B = \mu$, where $\theta_B$ is the polarising angle and $\mu$ is the refractive index of the medium.Explanation:For light going from air to glass, the Brewster's angle is $\theta$.So, $\tan \theta = \mu$, where $\mu$ is the refractive index of glass.When light propagates from glass to air, the relative refractive index becomes $\frac{1}{\mu}$.Let the new Brewster's angle be $\theta'$.Then, $\tan \theta' = \frac{1}{\mu}$.Substituting $\mu = \tan \theta$, we get $\tan \theta' = \frac{1}{\tan \theta} = \cot \theta$.Since $\cot \theta = \tan\left(\frac{\pi}{2} - \theta\right)$, it follows that $\theta' = \frac{\pi}{2} - \theta$.Therefore, the correct statement is option A.Answer:Option A.