MHTCET 23 Apr 2025 Shift 2 Paper

Concept:For a monoacidic base, the degree of dissociation is the ratio of the hydroxide ion concentration produced to the initial base concentration.Explanation:The pH of the monoacidic base solution is given as $10$.Hence, $pOH = 14 - pH = 14 - 10 = 4$.The hydroxide ion concentration is:$$[OH^-] = 10^{-pOH} = 10^{-4} \, M$$Since the base is monoacidic, it produces one $OH^-$ ion per molecule.The given concentration of the base is $C = 0.01 \, M$.The degree of dissociation is:$$\alpha = \frac{[OH^-]}{C} = \frac{10^{-4}}{0.01} = \frac{10^{-4}}{10^{-2}} = 10^{-2} = 0.01$$Percentage dissociation is:$$\% \, \text{dissociation} = \alpha \times 100 = 0.01 \times 100 = 1\%$$Answer:The percentage dissociation is $1\%$, so the correct option is D.