MHTCET 25 Apr 2025 Shift 2 Paper

Concept:In a common emitter amplifier, the voltage gain equals the product of current gain and the ratio of collector resistance to input resistance.Explanation:The voltage gain formula is $A_v = \beta \cdot \frac{R_c}{R_{in}}$, where $\beta$ is the current gain, $R_c$ is the collector resistance, and $R_{in}$ is the input resistance.Here, $\beta = 62$, $R_c = 5\,\mathrm{k}\Omega = 5000\,\Omega$, and $R_{in} = 500\,\Omega$.Substituting these values gives $A_v = 62 \times \frac{5000}{500}$.Simplifying, $A_v = 62 \times 10 = 620$.Hence, the amplifier magnifies the input voltage by a factor of 620.The output voltage is calculated as $V_{out} = A_v \times V_{in}$.Given $V_{in} = 0.01\,\mathrm{V}$, we get $V_{out} = 620 \times 0.01 = 6.2\,\mathrm{V}$.Answer:The output voltage is $6.2\,\mathrm{V}$, which matches option B.