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MHTCET 25 Apr 2025 Shift 2 Paper

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Question : 54 of 150

Marks: +1, -0

Find the volume of 56 g dinitrogen at STP

11.2 Lit.
22.4 Lit.
44.8 Lit.
67.2 Lit.

Solution:

Concept:

At STP, one mole of any ideal gas occupies

22.4\ \mathrm{L}

.

Dinitrogen is

\mathrm{N}_2

, and its molar mass is

28\ \mathrm{g/mol}

.

Explanation:

Molar mass of dinitrogen:

M_{\mathrm{N}_2} = 2 \times 14 = 28\ \mathrm{g/mol}

.

Given mass of dinitrogen

= 56\ \mathrm{g}

.

Number of moles:

n = \frac{\text{mass}}{\text{molar mass}} = \frac{56}{28} = 2\ \mathrm{mol}

.

At STP,

1\ \mathrm{mol}

occupies

22.4\ \mathrm{L}

.

So, volume

= n \times 22.4 = 2 \times 22.4 = 44.8\ \mathrm{L}

.

Answer:

Option C:

44.8\ \mathrm{Lit}

.

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