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NCHMCT JEE 2025 Solved Paper

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Question : 27 of 200

Marks: +1, -0

Find the LCM of the numbers :

\frac{4}{9}, \frac{8}{15}, \frac{6}{9}, \frac{12}{21}, \frac{14}{33}

$\frac{160}{3}$
$\frac{168}{3}$
52
56

Solution:

Concept:

LCM of fractions

=

\frac{\text{LCM of numerators}}{\text{HCF of denominators}}

after reducing each fraction to lowest terms.

Explanation:

Reduce the fractions first:

\frac{6}{9} = \frac{2}{3}

and

\frac{12}{21} = \frac{4}{7}

.

So the fractions are:

\frac{4}{9},\ \frac{8}{15},\ \frac{2}{3},\ \frac{4}{7},\ \frac{14}{33}

.

LCM of numerators

4, 8, 2, 4, 14

is

56

.

HCF of denominators

9, 15, 3, 7, 33

is

1

.

Therefore, required LCM

= \frac{56}{1} = 56

.

Answer:

D.

56

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