Consider the whole number 127. Hence it can be converted into Binary into following steps127i)127=2(63)+1→1ii)63=2(31)+1→1iii)31=2(15)+1→1iv)15=2(7)+1→1v)7=2(3)+1→1vi)3=2(1)+1→1vii)1=2(0)+1→1(127)10→(1111111)2Hence, the binary of 127 is seven times 1 or (1111111).Now for the binary of the number after the point, we get0.25×2=0.5→00.5×2=1.0→0∴(0.25)10=(.01)2∴(127.25)−10=(1111111.01)2