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NDA Math Binomial Theorem
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© examsnet.com
Question : 10
Total: 50
How many terms are there in the expansion of
(
a
2
b
2
+
b
2
a
2
+
2
)
21
where
a
≠
0
,
b
≠
0
?
[NDA-II 2021]
21
22
42
43
Validate
Solution:
👈: Video Solution
(d)
(
a
2
b
2
+
b
2
a
2
+
2
)
21
⇒
[
(
a
b
+
b
a
)
2
]
21
=
(
a
b
+
b
a
)
42
Since, we know that number of terms in the expansion of
(
a
+
b
)
n
=
n
+
1
Hence, total number of terms
=
42
+
1
=
43
∴
Option (d) is correct.
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