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NDA Math Complex Numbers
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© examsnet.com
Question : 54
Total: 66
What is
(
√
3
+
i
√
3
−
i
)
6
equal to,where
i
=
√
−
1
[NDA II 2014]
1
1/6
6
2
Validate
Solution:
(
√
3
+
i
√
3
−
i
)
6
=
(
√
3
+
i
√
3
−
i
×
√
3
+
i
√
3
+
i
)
6
=
(
(
√
3
)
2
+
i
2
+
2
i
√
3
(
√
3
)
2
−
i
2
)
6
=
(
3
−
1
+
2
i
√
3
4
)
6
=
(
1
+
i
√
3
2
)
6
=
(
cos
π
3
+
i
sin
π
3
)
6
=
cos
2
π
+
i
sin
2
π
=
1
© examsnet.com
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