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© examsnet.com
Question : 28
Total: 34
The eccentricity of the hyperbola
16
x
2
−
9
y
2
=
1
is
[NDA II 2015]
3
5
5
3
4
5
5
4
Validate
Solution:
∵
16
x
2
−
9
y
2
=
1
or
x
2
(
1
4
)
2
−
y
2
(
1
3
)
2
=
1
Comparing with
x
2
a
2
−
y
2
b
2
=
1
∴
a
2
=
1
16
&
b
2
=
1
9
∵
e
=
√
1
+
b
2
a
2
∴
=
√
1
+
1
9
1
16
⇒
e
=
5
3
© examsnet.com
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