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NDA Math Coordinate System and Straight Line

For the next three (3) items that follow:

Consider the triangle ABC with vertices A(-2,3),B(2,1) and

c(1,2)

[NDA I 2015]

Question : 79 of 92

Marks: +1, -0

Solution:

Consider the vertices of the triangle,

A=(-2,3)

B=(2,1)

C=(1,2)

The coordinates of the centroid of a triangle is given by the formula

G\left(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\right)

Using the formula, we get the centroid as

G=\left(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\right)

=\left(\frac{-2+2+1}{3},\frac{3+1+2}{3}\right)

=\left(\frac{1}{3},\frac{6}{3}\right)

=\left(\frac{1}{3},2\right)

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