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NDA Math Definite Integrals
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© examsnet.com
Question : 17
Total: 62
π
2
∫
0
|sin x−cos x|dx is equal to
[NDA I 2019]
0
2(
√
2
−1)
2
√
2
2(
√
2
+1)
Validate
Solution:
(B)
Let
I
=
π
2
∫
0
|
sin
x
−
cos
x
|
d
x
=
π
4
∫
0
|
sin
x
−
cos
x
|
d
x
+
π
2
∫
π
4
|
sin
x
−
cos
x
|
d
x
=
π
4
∫
0
|
cos
x
−
sin
x
|
d
x
+
π
2
∫
π
4
|
sin
x
−
cos
x
|
d
x
=
(
s
i
n
x
+
c
o
s
x
)
|
0
π
4
+
(
−
c
o
s
x
+
s
i
n
x
)
|
π
4
π
2
= 2(
√
2
−1)
© examsnet.com
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