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NDA Math Definite Integrals
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© examsnet.com
Question : 40
Total: 62
If
∫
−
2
5
f
(
x
)
d
x
=
4
and
∫
0
5
{
1
+
f
(
x
)
}
d
x
=
7
then what is
∫
−
2
0
f
(
x
)
d
x
equal to ?
[NDA I 2016]
−
3
2
3
5
Validate
Solution:
5
∫
−
2
f
(
x
)
d
x
=
4
and
5
∫
0
{
1
+
f
(
x
)
}
d
x
=
7
5
∫
0
f
(
x
)
d
x
=
7
−
5
∫
0
1
d
x
=
7
−
5
=
2
....(1)
0
∫
−
2
f
(
x
)
d
x
=
?
0
∫
−
2
f
(
x
)
d
x
+
5
∫
0
f
(
x
)
d
x
=
4
0
∫
−
2
f
(
x
)
d
x
=
4
−
5
∫
0
f
(
x
)
d
x
=
4
−
2
=
2
[Using eqn. (1)]
0
∫
−
2
f
(
x
)
d
x
=
2
© examsnet.com
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