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NDA Math Determinants
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© examsnet.com
Question : 35
Total: 68
The system of equation
k
x
+
y
+
z
=
1
,
x
+
k
y
+
z
=
k
and
x
=
y
+
k
z
=
k
2
has no solution if k equals
[NDA II 2017]
0
1
−
1
−
2
Validate
Solution:
|
k
1
1
1
k
1
1
1
k
|
=
0
⇒
k
(
k
2
−
1
)
−
(
k
−
1
)
+
(
1
−
k
)
=
0
⇒
k
(
k
+
1
)
−
1
−
1
]
=
0
⇒
k
2
+
k
−
2
=
0
⇒
1
,
−
2
For
k
=
1
, first two equations will become same.
⇒
k
=
−
2
© examsnet.com
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