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NDA Math Determinants
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© examsnet.com
Question : 9
Total: 68
If
|
a
−
b
a
−
b
−
c
−
a
b
−
a
+
b
−
c
−
a
−
b
−
a
−
b
+
c
|
−
k
a
b
c
=
0
(
a
≠
0
,
b
≠
0
,
c
≠
0
)
then what is the value of
k
?
[NDA-II 2021]
−
4
−
2
2
4
Validate
Solution:
👈: Video Solution
(a) Given that,
|
a
−
b
a
−
b
−
c
−
a
b
−
a
+
b
−
c
−
a
−
b
−
a
−
b
+
c
|
−
k
a
b
c
=
0
(
a
≠
0
,
b
≠
0
,
c
≠
0
)
|
0
0
−
2
c
−
a
b
−
a
+
b
−
c
−
a
−
b
−
a
−
b
+
c
|
−
k
a
b
c
=
0
−
2
c
[
(
−
a
)
(
−
b
)
−
(
−
a
)
b
]
−
k
a
b
c
=
0
−
2
c
(
2
a
b
)
−
k
a
b
c
=
0
−
k
a
b
c
=
4
a
b
c
k
=
−
4
© examsnet.com
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