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NDA Math Differential Equation
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© examsnet.com
Question : 42
Total: 70
What is the differential equation corresponding to
y
2
−
2
a
y
+
x
2
=
a
2
by eliminating a ?
[NDA I 2017]
(
x
2
−
y
2
)
p
2
−
4
p
x
y
−
2
x
2
=
0
(
x
2
−
2
y
2
)
p
2
+
4
p
x
y
−
x
2
=
0
(
x
2
+
2
y
2
)
p
2
−
4
p
x
y
−
x
2
=
0
(
x
2
+
y
2
)
p
2
−
4
p
x
y
+
x
2
=
0
Validate
Solution:
y
2
−
2
a
y
+
x
2
=
a
2
⇒
2
y
d
y
d
x
−
2
a
d
y
d
x
+
2
x
=
0
⇒
y
d
y
d
x
+
x
d
y
d
x
=
a
⇒
p
y
+
x
p
=
a
⇒
y
2
−
2
y
(
p
y
+
x
)
p
+
x
2
=
(
p
y
+
x
p
)
2
⇒
p
2
y
2
−
2
p
2
y
2
−
2
x
y
p
+
p
2
x
2
=
p
2
y
2
+
x
2
+
2
x
y
p
⇒
−
2
p
2
y
2
+
p
2
x
2
−
4
x
y
p
−
x
2
=
0
⇒
p
2
(
x
2
−
2
y
2
)
−
4
x
y
p
−
x
2
=
0
© examsnet.com
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