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NDA Math Inverse Circular Functions
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© examsnet.com
Question : 7
Total: 25
If
s
i
n
x
=
1
√
5
,
s
i
n
y
=
1
√
10
,where
0
<
x
<
π
2
then what is (x+y) equal to ?
[NDA I 2018]
π
π
2
π
4
0
Validate
Solution:
sinx
=
1
√
5
,
siny
=
1
√
10
sin
(
x
+
y
)
=
sinx
⋅
cosy
+
cosx
siny
cosx
=
√
1
−
1
5
=
2
√
5
cosy
=
√
1
−
1
10
=
√
9
10
=
3
√
10
sin
(
x
+
y
)
=
1
√
5
×
3
√
10
+
2
√
5
×
1
√
10
=
5
√
50
=
1
√
2
⇒
x
+
y
=
45
∘
© examsnet.com
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