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NDA Math Matrices
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© examsnet.com
Question : 13
Total: 69
If
A
=
[
1
a
0
1
]
, where
a
∈
ℕ
, then what is
A
100
−
A
50
−
2
A
25
equal to?
[NDA-II 2021]
−
21
−
1
21
I
where
I
is the identity matrix.
Validate
Solution:
👈: Video Solution
(a)
A
=
[
1
a
0
1
]
a
∈
mathbb
N
The sequence for given matrix
A
is
A
n
=
[
1
na
0
1
]
∴
A
100
−
A
50
−
2
A
25
=
[
1
100
a
0
1
]
−
[
1
50
a
0
1
]
−
2
[
1
25
a
0
1
]
=
[
1
−
1
−
2
100
a
−
50
a
−
50
a
0
−
0
−
0
1
−
1
−
2
]
=
[
−
2
0
0
−
2
]
=
−
21
© examsnet.com
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