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NDA Math Polygons and Quadrilaterals

Direction : Consider the following for the next two (02) items that follow.

The coordinates of three consecutive vertices of a parallelogram

A B C D

are

A(1,3), B(-1,2)

and

C(3,5)

[NDA-II 2021]

Question : 7 of 12

Marks: +1, -0

Solution: 👈: Video Solution

The vertices of parallelogram are

A(1,3), B(-1,2), C(3,5)

and

D(5,6)

\therefore

Area

=|

Area of

\triangle ABC+

Area of

\triangle ACD |

= \frac{1}{2}\left|1(2-5)-1(5-3)+3(3-2)\right|

+ \frac{1}{2}\left|1(5-6)+3(6-3)+5(3-5)\right|

= \frac{1}{2}\left|-3-2+3+(-1)+9-10\right|

= 2 \text{ sq. units}

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