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NDA Math Probability
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© examsnet.com
Question : 83
Total: 100
In throwing of two dice, the number of exhaustive events that ‘5’ will never appear on any one of the dice is
[NDA I 2015]
5
18
25
36
Validate
Solution:
Let A be the set of the required elements and S be the sample space.Hence,
S
=
{
(
1
,
1
)
,
(
1
,
2
)
,
(
1
,
3
)
,
(
1
,
4
)
,
(
1
,
5
)
,
(
1
,
6
)
(
2
,
1
)
,
(
2
,
2
)
,
(
2
,
3
)
,
(
2
,
4
)
,
(
2
,
5
)
,
(
2
,
6
)
(
3
,
1
)
,
(
3
,
2
)
,
(
3
,
3
)
,
(
3
,
4
)
,
(
3
,
5
)
,
(
3
,
6
)
(
4
,
1
)
,
(
4
,
2
)
,
(
4
,
3
)
,
(
4
,
4
)
,
(
4
,
5
)
,
(
4
,
6
)
(
5
,
1
)
,
(
5
,
2
)
,
(
5
,
3
)
,
(
5
,
4
)
,
(
5
,
5
)
,
(
5
,
6
)
(
6
,
1
)
,
(
6
,
2
)
,
(
6
,
3
)
,
(
6
,
4
)
,
(
6
,
5
)
(
6
,
6
)
}
n
(
S
)
=
36
Therefore the number of elements in A will be
n
(
A
)
=
n
(
S
)
−
n
(Elements with 5)
=
36
−
6
−
5
=
25
© examsnet.com
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