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NDA Math Properties of Triangles
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© examsnet.com
Question : 11
Total: 16
In a triangle ABC,
a
−
2
b
+
c
=
0
.The value of
cot
(
A
2
)
cot
(
C
2
)
is
[NDA II 2017]
9
3
3
3
2
1
Validate
Solution:
a
+
b
=
2
b
cot
A
2
⋅
cot
c
2
=
√
s
(
s
−
a
)
(
s
−
b
)
(
s
−
c
)
×
s
(
s
−
c
)
(
s
−
a
)
(
s
−
b
)
=
s
s
−
b
=
2
s
2
s
−
2
b
=
a
+
b
+
c
a
+
b
+
c
−
2
b
=
3
b
b
=
3
© examsnet.com
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