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NDA Math Quadratic Equations and Inequations
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© examsnet.com
Question : 60
Total: 67
The number of real roots of the equation
x
2
−
3
|
x
|
+
2
=
0
is
[NDA II 2015]
4
3
2
1
Validate
Solution:
x
2
−
3
|
x
|
+
2
=
0
Case (i) when
x
≥
0
x
2
−
3
x
+
2
=
0
(
x
−
1
)
(
x
−
2
)
=
0
x
=
1
,
2
(both roots satisfy the condition
x
≥
0
)
Case(ii) when
x
<
0
x
2
+
3
x
+
2
=
0
(
x
+
1
)
(
x
+
2
)
=
0
x
=
−
1
,
−
2
(both roots satisfy the condition
x
<
0
)
So no. of real roots is 4.
© examsnet.com
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