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NDA Math Three Dimensional Geometry
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© examsnet.com
Question : 29
Total: 92
What is the radius of the sphere x
2
+ y
2
+z
2
−6 x+ 8y− 10z+1=0 ?
[NDA I 2019]
5
2
7
3
Validate
Solution:
(C)
Given equation of sphere is
x
2
+ y
2
+ z
2
− 6 x + 8y − 10z+1 = 0
⇒ ( x
2
− 6 x + 9) − 9 + ( y
2
+ 8 y + 16) − 16 + ( z
2
− 10 z + 25) − 25 + 1 = 0
⇒ ( x−3)
2
+ ( y+4)
2
+ ( z−5)
2
= 49
∴ Radius of given sphere = 7
© examsnet.com
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