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Test Index
NDA Math Trigonometric Ratios of Angles and Equations Part 2
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© examsnet.com
Question : 38
Total: 75
What is
1
+
tan
2
θ
1
+
cot
2
θ
−
(
1
−
tan
θ
1
−
cot
θ
)
2
equal to?
[NDA-I 2021]
0
1
2
tan
θ
2
cot
θ
Validate
Solution:
👈: Video Solution
Concept:
Trigonometry Formula
sec
2
θ
=
1
+
tan
2
θ
c
o
s
e
c
2
θ
=
1
+
cot
2
θ
cot
θ
=
1
tan
θ
sec
θ
=
1
cos
θ
c
o
s
e
c
θ
=
1
sin
θ
Calculation:
1
+
tan
2
θ
1
+
cot
2
θ
−
(
1
−
tan
θ
1
−
cot
θ
)
2
=
sec
2
θ
c
o
s
e
c
2
θ
−
(
1
−
tan
θ
1
−
1
tan
θ
)
=
1
cos
2
θ
1
sin
2
θ
−
(
1
−
tan
θ
tan
θ
−
1
tan
θ
)
=
sin
2
θ
cos
2
θ
−
(
1
−
tan
θ
−
(
1
−
tan
θ
)
tan
θ
)
=
tan
2
θ
−
(
−
tan
θ
)
2
=
tan
2
θ
−
tan
2
θ
=
0
© examsnet.com
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