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NDA Math Trigonometric Ratios of Angles and Equations
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© examsnet.com
Question : 22
Total: 100
If
θ
=
π
8
then what is the value of
(
2
cos
θ
+
1
)
10
(
2
cos
2
θ
−
1
)
10
(
2
cos
θ
−
1
)
10
(
2
cos
4
θ
−
1
)
10
?
[NDA II 2018]
0
1
2
4
Validate
Solution:
[
(
2
cos
θ
+
1
)
(
2
cos
θ
−
1
)
]
10
[
2
cos
2
θ
−
1
]
10
[
2
cos
4
θ
−
1
]
10
,
θ
=
π
8
=
(
4
cos
2
π
8
−
1
)
10
(
2
×
1
√
2
−
1
)
10
(
−
1
)
10
=
(
4
×
2
+
√
2
4
−
1
)
10
(
√
2
−
1
)
10
=
[
(
√
2
+
1
)
(
√
2
−
1
)
]
10
=
1
10
=
1
© examsnet.com
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