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NDA Math Trigonometric Ratios of Angles and Equations
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© examsnet.com
Question : 48
Total: 100
If
t
a
n
(
α
+
β
)
=
2
and
t
a
n
(
α
−
β
)
=
1
,
then
t
a
n
(
2
α
)
is equal to
[NDA I 2017]
−
3
−
2
−
1
3
1
Validate
Solution:
tan
2
α
=
tan
(
α
+
β
+
α
−
β
)
=
tan
(
a
+
β
)
+
tan
(
α
−
β
)
1
−
tan
(
a
+
β
)
tan
(
α
−
β
)
=
2
+
1
1
−
2
×
1
=
3
−
1
=
−
3
© examsnet.com
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