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NEET 2018 Physics and Chemistry
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© examsnet.com
Question : 41
Total: 90
A moving block having mass m, collides with another stationary block having mass 4m. Thelighter block comes to rest after collision.When the initial velocity of the lighter block isv, then the value of coefficient of restitution(e) will be
[NEET 2018]
0.5
0.25
0.4
0.8
Validate
Solution:
👈: Video Solution
According to law of conservation of linear momentum,
m
v
+
4
m
×
0
=
4
m
v
′
+
0
v
′
=
v
4
e
=
Relative velocity of separation
Relative velocity of approach
=
v
4
v
e
=
1
4
=
0.25
© examsnet.com
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