Acceleration a=16−0=6m/s2For t=0 to t=1s, S1=21×6(1)2=3m...(i)For t=1s to t=2sS2=6.1−21×6(1)2=3m....(ii)For t=2s to t=3sS3=0−21×6(1)2=−3m...(iii)Total displacement S=S1+S2+S3=3m Average velocity =33=1ms−1Total distance travelled=9mAverage speed=39=3ms−1