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NEET 2020 Model Question Paper 1
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© examsnet.com
Question : 10
Total: 180
A ring of mass m is attached to a horizontal spring of spring constant k and natural length
l
0
. Other end of spring is fixed and ring can slide on a smooth horizontal rod as shown. Now the ring is shifted to position B and released, speed of ring when spring attains it's natural length is :-
2
l
0
3
√
k
m
l
0
3
√
k
m
3
l
0
2
√
k
m
l
0
√
k
m
Validate
Solution:
cos
53
°
=
l
0
l
0
+
x
3
5
=
l
0
l
0
+
x
x
=
2
3
l
0
from B → A
1
2
k
x
2
=
1
2
m
v
2
v
=
x
√
k
m
=
2
3
l
0
√
k
m
© examsnet.com
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