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NEET 2022 Model Paper 1
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© examsnet.com
Question : 21
Total: 200
A
50
c
m
long wire has mass of
20
g
linearly distributed. This string is under a tension of
16
N
. The speed of transverse pulse generated on it is
2
m
∕
s
10
m
∕
s
20
m
∕
s
15
m
∕
s
Validate
Solution:
µ
=
m
L
=
20
×
10
−
3
50
×
10
−
2
=
0.04
k
g
m
−
1
T
=
16
N
V
=
√
T
µ
=
√
16
0.04
=
√
16
×
100
4
=
√
400
=
20
m
∕
s
© examsnet.com
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